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C++ solution:
void plusMinus(vector<int> arr, int n) { int count_negative=0, count_zero=0, count_positive=0; for(int i=0; i<n; i++){ arr[i] < 0 ? count_negative++ : arr[i]>0 ? count_positive++ : count_zero++; } cout << fixed << setprecision(6) << count_positive/(n*1.0) << "\n" << count_negative/(n*1.0) << "\n" << count_zero/(n*1.0) ; }
ty man you improved my skills with your code-style
Beaufitul. I agree this is elegant and understandable. =)
that's an a++ solution in my book :p
Plus Minus
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C++ solution:
ty man you improved my skills with your code-style
Beaufitul. I agree this is elegant and understandable. =)
that's an a++ solution in my book :p