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  1. Prepare
  2. Python
  3. Regex and Parsing
  4. Re.findall() & Re.finditer()
  5. Discussions

Re.findall() & Re.finditer()

  • giacgbj
     + 34 comments

    The regexes I saw can be shortened using either a positive lookbehind or a positive lookahed. I don't think it can be solved without them because you have to avoid consuming the input somewhere (before or after).

    Using the positive lookbehind:

    import re
v = "aeiou"
c = "qwrtypsdfghjklzxcvbnm"
m = re.findall(r"(?<=[%s])([%s]{2,})[%s]" % (c, v, c), input(), flags = re.I)
print('\n'.join(m or ['-1']))

    Using the positive lookahead, same as above with the regex:

    [%s]([%s]{2,})(?=[%s])