• + 0 comments

    Here's a Javascript solution:

    function repeatedString(s, n) {
        const remaining = Math.round((n / s.length - Math.floor(n / s.length)) * s.length);
        const aInSingle = (s.match(/a/g) || []).length;
        return Math.floor(n/s.length)*aInSingle + (s.substring(0,remaining).match(/a/g) || []).length
    }