• + 19 comments
    int main(){
        string s;
        cin >> s;
        long n;
        cin >> n;
        long count=0;
        int i,k=s.size();
        long p=n/k;
        
          for(i=0;i<s.size();i++){
            if(s[i]=='a')
                count++;
          }
        
        count = count * p;
        
        for(i=0;i<(n%s.size());i++){
            if(s[i]=='a')
                count++;
        } 
        cout << count << endl;
            return 0;
    }
    

    More simplified cpp solution,i hope this will be heplful