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  1. Prepare
  2. Algorithms
  3. Strings
  4. Sherlock and the Valid String
  5. Discussions

Sherlock and the Valid String

  • guptap8265
     + 0 comments

    def isValid(s):

    c = set(s)
l = []
result = "YES"
for i in c:
    k = s.count(i)
    l.append(k)
if(max(l) == min(l)):
    return result
if(max(l)-min(l)== 1):
    if(l.count(min(l))<2 or l.count(max(l))<2):
        return result
    else:
        result = "NO"
        return result
if(min(l) == 1 and l.count(min(l)==1) and l.count(max(l))==len(l)-1):
    return result
else:
    result = "NO"  
    return result