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  1. Prepare
  2. Algorithms
  3. Strings
  4. Sherlock and the Valid String
  5. Discussions

Sherlock and the Valid String

  • samuelpedrajaspz
     + 0 comments

    My Python solution:

    def isValid(w):
    freq_counter = Counter(w)
    freq_freq = Counter(freq_counter.values())

    if len(freq_freq) == 1:
        return "YES"
    elif len(freq_freq) == 2:
        (k1, v1), (k2, v2) = freq_freq.items()
        if v1 == 1 and (k1 - 1 == k2 or k1 == 1) or v2 == 1 and (k2 - 1 == k1 or k2 == 1):
            return "YES"
    return "NO"