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  1. Prepare
  2. Algorithms
  3. Debugging
  4. Smart Number
  5. Discussions

Smart Number

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127 Discussions

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  • patrickgao2020
     + 0 comments

    This is the finished Python code. You should change "if num / val == 1:" to "if num / val == val".

    import math

def is_smart_number(num):
    val = int(math.sqrt(num))
    if num / val == val:
        return True
    return False

for _ in range(int(input())):
    num = int(input())
    ans = is_smart_number(num)
    if ans:
        print("YES")
    else:
        print("NO")

  • alban_tyrex
     + 0 comments

    Here is my c++ solution, you can watch video explanation here : https://youtu.be/Qs9rxqfzTs8

    bool is_smart_number(int num) {
    int val = (int) sqrt(num);
    if(val * val == num)
        return true;
    return false;
}

  • emhhacker
     + 0 comments

    For Java coders: change line 10 to:

            if(val * val == num)

    A smart number is only smart if its a perfect square.

  • Rithuterese
     + 0 comments

    bool is_smart_number(int num) { if(num<=0) return false;

    int val = (int) sqrt(num);
if(val * val == num)
    return true;
return false;

    }

    Its correct but compiling false

  • gireendravarma
     + 0 comments

    Why this problem doesnt support JavaScript language

    function isSmartNumber(num) {
    var val = Math.floor(Math.sqrt(num));
    if (val * val === num) {
        return true;
    }
    return false;
}