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bool is_smart_number(int num) { if(num<=0) return false;
int val = (int) sqrt(num); if(val * val == num) return true; return false;
}
Its correct but compiling false
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Smart Number
You are viewing a single comment's thread. Return to all comments →
bool is_smart_number(int num) { if(num<=0) return false;
}
Its correct but compiling false