We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
Loading...
  1. Practice
  2. Algorithms
  3. Warmup
  4. Staircase
  5. Discussions

Staircase

  • RandhyllCho + 4 comments

    I made this work in Swift by overloading the operator

    var n = Int(readLine()!)!

func *(string: String, scalar:Int) -> String {
    let value = Array(count: scalar, repeatedValue: string)
    return value.joinWithSeparator("")
}

for i in 1..<n + 1 {
    print(" " * (n - i) + "#" * i)
}

    https://developer.apple.com/library/ios/documentation/Swift/Conceptual/Swift_Programming_Language/AdvancedOperators.html

    • kmkrn + 0 comments

      This is pretty elegant. And I've created a monster:

      var array = Array(arrayLiteral: space)
for i in 1...n-1{
    array.append(" ")
}
array[n - 1] = "#"
for i in 1...n{
    array[n - i] = "#"
    var string = array.joinWithSeparator("")
    print(string)
}
    • Eddie_Dou + 0 comments

      Great! my way is trying to stitch sring directly via '+', silly.

    • nemanja1 + 2 comments

      My solution: 

      let space = Character(" ")
let char = Character("#")

var spaceCount = 0
var charCount = 0

for (var i = 0; i<n; i++) {
    spaceCount = n-1-i
    charCount = i+1
    let spaceString = String(count: spaceCount, repeatedValue: space)
    let charString = String(count: charCount, repeatedValue: char)
    print("\(spaceString)\(charString)")
}
      • liverdye + 1 comment

        Could you explain the "let" function (for lack of a better term)? Is it used in Python 2? I can't find an explanation of it online. Thank you!:)

        • paul31 + 1 comment

          That's not Python it's Swift.

          • liverdye + 0 comments

            Oh gotcha. Thanks!:D

      • paul31 + 1 comment

        Mine was very similar, only real difference is that my for loop is ready for Swift 3... 

        var n = Int(readLine()!)!
for i in 1...n {
    var row = ""
    let spaces = n-i
    let hashes = n-spaces
    row += String(count: spaces, repeatedValue: Character(" "))
    row += String(count: hashes, repeatedValue: Character("#"))
    print(row)
}
        • SteveMartinClark + 0 comments

          // Current Syntax Is

          for i in 1...n {
  var row = ""
  let spaces = n-i
  let hashes = n-spaces
  row += String(repeating: Character(" "), count: spaces)
  row += String(repeating: Character("#"), count: hashes)
  print(row)
}
    • Kijit + 2 comments

      how about this ?

      for i in 1...n {
    print(String(repeating: " ", count: n - i) + String(repeating: "#", count: i))
}
      • Codeglee + 0 comments

        Thanks Kijit TIL! That repeating constructor is super handy to know about.

      • sergeyoleynich + 0 comments

        More swift like solution

        (1...n).forEach { value in
        print(String(repeating: " ", count: n - value) + String(repeating: "#", count: value))
    }

        or use reduce function

        print((1...n).reduce(into: "") { result, value in
        result.append(String(repeating: " ", count: (n - value)))
        result.append(String(repeating: "#", count: value))
        result.append("\n")
    })

        I do not know about the complexity.