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  1. Practice
  2. Algorithms
  3. Warmup
  4. Staircase
  5. Discussions

Staircase

  • mamoun003 + 15 comments

    python is love,,,,python is life

    n = int(input())
for i in range(1,n+1):
  print(('#'*i).rjust(n,' '))
    • kalez + 0 comments

      nice,

    • uyuyliu + 0 comments

      AMAZING

    • snchzantonio + 4 comments

      I updated my answer based on yours

      n = int(input())
[print(("#"*f).rjust(n) ) for f in range(1,n+1)]
      • jarrod505 + 1 comment

        My answer was similar, I concatenated instead of justified

        [print(' '*(n-i) + '#'*i) for i in range(1,n+1)]
        • phderome + 0 comments

          like my Scala solution, same idea.

      • greenhand1 + 2 comments

        if you don't want to use rjust. You can simply add space yourself

        for length in range(n):
    print(' '*(n-length-1)+'#'*(length+1))
        • croqaz + 0 comments
          for i in range(1, n+1):
    print(' ' * (n-i) + '#' * i)
        • hualing_yu + 0 comments

          Same idea!

          for i in range(n):
    print(" "*(n-i-1)+"#"*(i+1))
      • michelbetancour1 + 1 comment

        one liner

        (lambda num: [print(('#'*x).rjust(num)) for x in range(num+1)])(int(input().strip()))
        • mahamadbilal696 + 0 comments

          i have got the error as follows...

          (lambda num: [print(('#'*x).rjust(num)) for x in range(num+1)])(int(input().strip())) ^ SyntaxError: invalid syntax

          can you please help me why it so.....

      • mjamal + 0 comments
        for pound, space in zip(list(range(1,n+1)), reversed(list(range(1,n+1)))):
                print(' '*space + '#'*pound)

        Is there something wrong with this answer? Cannot pass the test case.

    • RANA5069 + 1 comment

      Bro...how the n value in rjust() is decreasing...first it will print n spaces than in next iteration what will happen..please explain

      • andy66 + 0 comments

        rjust does not add n spaces to the string, it makes the string n spaces long in total

    • ruturaj_haval + 2 comments

      Will Someone please explain me this python code ? I know how to do it using 2 loops

      • thanhtrung674 + 2 comments

        firstly, he prints it without the spaces, so it looks like this

        #
##
###
####

        then he uses rjust just to right justify the above string and fill the empty gaps with spaces. Afer that, it looks like this:

           #
  ##
 ###
####

        Sorry for my bad english

        • ruturaj_haval + 0 comments

          Thank you. I understood the code.

        • patricia_paulss1 + 0 comments

          Your english is fine

      • prashy_shtty + 1 comment

        try this

        count = 1
while(count <= n):
    print(('#' * count).rjust(n))
    count += 1
        • eshad0603 + 1 comment

          what is the main function of rjust?

          • prashy_shtty + 0 comments

            right justification

    • an0o0nym + 3 comments

      Python3 is even more love:

      for i in range(n):
    print('{:>{len}}'.format('#'*(i+1), len=n))

      You can also do it pretty easy as a one-liner :)

      • sayalijoshi30 + 0 comments

        Thanks :)

      • upaliwal17 + 0 comments

        pls explain this code,cant understand.

      • dansiman + 0 comments

        I did it a little less concisely:

        line = 1
stair = ""
while line <= n:
    stair += "#"
    print(str(stair).rjust(n))
    line += 1
    • FeruzOripov + 0 comments

      thanks)

    • dst_hr_91 + 0 comments

      Neat and great solution !!

    • pk8010 + 0 comments

      Really it is very fantastic I was trying for i in range(n): k = n while k>i+1: print ' ', k -= 1 for j in range(i+1): print '#', print

    • mahamadbilal696 + 0 comments

      Thank you

    • phderome + 0 comments

      similar to my Scala code. I guess Scala creators borrowed from Java, Python, and Haskell quite a few ideas.

    • flowfelis + 0 comments

      you don't need the second argument in rjust, default is space already ;)

    • shubhambigdream + 1 comment

      my output is same but still showing fail, can anybody tell me whats wrong:

      • Kanahaiya + 2 comments

        show me your code?

        • shubhambigdream + 0 comments

          a=int(input())+1 i=0 while(a!=0): print(" "*a,end="") print("#"*i) a=a-1 i=i+1

        • shubhambigdream + 1 comment

          didi u find anything

          • Kanahaiya + 0 comments

            Could you please format your code or do one thing if its not in java then cross verify your solution with mine one. It will help you to figure out the mistake at your own.

            Here is the video explanation –

            https://youtu.be/gDltV7pJw7A

    • maqsudinamdar7 + 1 comment

      I'm beginner in python. Can you explain me this code

      • prashy_shtty + 0 comments

        simpler one count = 1 while(count <= n): print(('#' * count).rjust(n)) count += 1

    • fenwicknate + 0 comments

      Good Evening! I was amazed at your succinct and easy solution to this problem. I am currently getting my feet wet in Python and have been using Hackerrank in order to improve my familiarity with it along with its online documentation.

      I main question is this: How did you know that you could use print('#'*1) I have scoured programiz.com and Stack Overflow for ideas on handling this problem, but this technique never came up.

      Any lead on becoming a better python programmer would be greatly appreciated!