We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
Loading...
  1. Practice
  2. Algorithms
  3. Warmup
  4. Staircase
  5. Discussions

Staircase

  • neil_cuajotor + 1 comment

    nice puzzle mate but it seems pretty confusing

    • CodeAcharya + 6 comments

      How about this mate

      public class Solution {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        for(int i=1;i<=n;i++)
        {
             for(int k=n;k>i;k--)
             {
                 System.out.printf(" ");
             }    
             for(int j=1;j<=i;j++)
             {
                 System.out.printf("#");
             }
            System.out.println();
        }
    }
}
      • deekshithsagar73 + 0 comments

        might

      • joaquimley + 3 comments

        3 nested for loops? There's def. something to be improved here, think about recursion.

        • tatianaensslin + 0 comments

          its really only 2 nested for loops and therye each operating on different ranges.

        • benaffleks + 1 comment

          2 nested loops and the size is extremely small so computation time is not something we need to consider

          • bineykingsley36 + 0 comments

            how do you see my Python 2 solution?

        • dallas3 + 1 comment
          function createString(str, ns, n) {
    if (ns > 0) return createString(str+" ", ns-1, n);
    else if (n > 0 && ns === 0) return createString(str+"#", ns, n-1);
    else if (n === 0 && ns === 0) return str;
}

// Complete the staircase function below.
function staircase(n) {
   let ns = n.length-1;
    console.log(createString("", ns, n));

}

          i was going to add a while loop but i keep getting undefined not sure the problem.

          • dallas3 + 0 comments

            okay im an idiot and for some reason put n.length as if a int has a length.

      • hissamrocks + 0 comments

        fantastic idea dude

      • vigneshwar028 + 0 comments

        can you explain this ?

      • Callum_g_anders1 + 0 comments

        That was my solution basically as well. I like it ;)

      • Phiber_Optik + 1 comment

        i m still confused with the logic, can you please explain it furthure more?

        • bineykingsley36 + 1 comment
          1. I loop from 1 to the maximum number (n).
          2. And then I print a number of # amounting to the current loop index on each line followed with a newline break.
          3. But since this will lead to the output being aligned on the left, I also print (n-i) spaces on each line where n is the maximum number and i is the current loop index before executing (2). So for instance when i is 1, I print 5 spaces before I print 1 # to fill up the six spaces (total number of spaces on each line). When i is 2, I print 4 spaces before I print 2 # to make sure all the six spaces on the line are filled. This also ensures that the # is aligned to the right.

          NB. The range is (1, n+1). I didn't start from 0 because that will cause an empty space at the beginning of the output and I also ended at n+1 because the loop ends and n-1 so I add 1 to get to the correct n.

          Do you get it now?

          • Phiber_Optik + 1 comment

            Yes! you explained it awesome. Thank you man!