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- Artificial Intelligence
- Probability & Statistics - Foundations
- Standard Deviation Puzzles - 5
- Discussions
Standard Deviation Puzzles - 5
Standard Deviation Puzzles - 5
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SD[X] = sqrt(expectation[(X-mean)**2]) if every X is added 10 units, the mean will be 45 (prev mean) + 10. So the new SD[X]: SD[X+10] = sqrt(expectation[(X+10-(mean+10))**2]) = sqrt(expectation[(X-mean))**2]) = SD[X] (old std.dev)
original_sd = 10 new_sd = original_sd print(f"{new_sd:1f}")
The checker is broken. It accepts 9.9 and 10.1 values, while none of them are actually correct.
SD is constant and stays almost the same