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SD[X] = sqrt(expectation[(X-mean)**2])
if every X is added 10 units, the mean will be 45 (prev mean) + 10.
So the new SD[X]:
SD[X+10] = sqrt(expectation[(X+10-(mean+10))**2])
= sqrt(expectation[(X-mean))**2])
= SD[X] (old std.dev)
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Standard Deviation Puzzles - 5
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SD[X] = sqrt(expectation[(X-mean)**2]) if every X is added 10 units, the mean will be 45 (prev mean) + 10. So the new SD[X]: SD[X+10] = sqrt(expectation[(X+10-(mean+10))**2]) = sqrt(expectation[(X-mean))**2]) = SD[X] (old std.dev)