Discussion on Validating UID Challenge

6 days ago+ 0 comments

I have used regex to solve this problem, and some python logics.

I have created 3 differents patterns (1 for each condition, except the last one which check at the same time if the UID is exactly 10 characters).

first condition pattern check if 2 uppercase (at least) are present or not.

Note : ?. is a lookaround operators and it means anything before an uppercase. So "....A....". This format must be repeated at least twice : {2,}

Exact same logics with digits 0-9

And the last pattern, I think, is logic to understand, we only want a-zA-Z0-9 characters exactly 10 times.

Then, we just have to check condition by condition.

Here my code, I am pretty sure there is a simple way or more concise way to solve this problem, but, it works and the logics sounds good :

# Enter your code here. Read input from STDIN. Print output to STDOUT
import re

T = int(input())

UID_list = list()

for _ in range(T):
    current_UID = input()
    UID_list.append(current_UID)
    
# Patterns
first_condition_pattern = r'^(?=(?:.*[A-Z]){2,}).*$'

second_condition_pattern = r"^(?=(?:.*[0-9]){3,}).*$"

third_condition_pattern = r"[a-zA-Z0-9]{10}"

for element in UID_list:
    
    if len(set(element)) != len(list(element)):
        #print("Repeat character")
        print("Invalid")

    elif bool(re.match(first_condition_pattern, element)) == False:
        #print("Not 2 upper case minimum")
        print("Invalid")
    
    elif bool(re.match(second_condition_pattern, element)) == False:
        #print("Not 3 digits minimum")
        print("Invalid")
    
    elif bool(re.match(third_condition_pattern, element)) == False:
        #print("Not only alphanumeric character or not exactly 10 characters")
        print("Invalid")
    
    else:
        print("Valid")

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