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  1. Practice
  2. SQL
  3. Basic Select
  4. Weather Observation Station 5
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Weather Observation Station 5

  • sneha_jadhav + 2 comments

    SQL SERVER

    select top 1 city, len(city) from Station order by len(city)asc, city;

    select top 1 city, len(city) from Station order by len(city)desc, city;

    • Vishal_Patel + 2 comments

      why added ",city" at the end?

      • piriys + 1 comment

        Because if there are multiple results with the same length you will have to get the result that comes first alphabetically.

        The ASC in the end of it can be ignored but I like to put them in for clarification :)

        SELECT TOP 1 CITY, LEN(CITY) AS LENGTH
FROM STATION 
ORDER BY LEN(CITY) ASC, CITY ASC;

SELECT TOP 1 CITY, LEN(CITY) AS LENGTH
FROM STATION 
ORDER BY LEN(CITY) DESC, CITY ASC;
        • csuttonmajor + 0 comments

          Yes, thank you. Clarity. This is what I came up with.

      • codymitchell1018 + 0 comments

        If someone still doesn't understand,

        basically with the ORDER BY clause you can sort by multiple things, not just one. So in this example,

        when the following code is executed:

        ORDER BY LEN(CITY), CITY

        you are first ordering by LEN(CITY) meaning that the query will order the results by the length of the city name.

        So all of the city names with 3 letters, then 4, then 5, and so on....

        But, this is all it does, and it will not order them any other way because you did not explicity say to do so. So now the length of the city name is sorted in ascending order, but the results are not alphabetical. This is where the ,CITY part comes in.

    • deepalisingh207 + 1 comment

      what if there are more than 1 city with min. length??

      • ragamx + 0 comments

        I resolved it like this

        select city, length(city) from station where length(city) in (select max(length(city)) from station) order by city limit 1;

        select city, length(city) from station where length(city) in (select min(length(city)) from station) order by city limit 1;