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a simple solution:
select small.a,b from
(select city a,length(city) b
from station
order by b, a)small where rownum=1
union
select big.a,b from
(select city a , length(city)b
from station
order by b desc ,a desc)big
where rownum=1;
select city,length(city) from (select city , length(city) from (select city from station order by length(city)) as a order by length(city),city limit 1) as b
union all
select city,length(city) from (select city , length(city) from (select city from station order by length(city)) as c order by length(city) desc,city limit 1) as d
wrong.
In the last query should be ordered by b desc, a ASC as we have to take the first alphabetically. But the table seems to have only one city with the largest string so you get luckily the expected results.
Weather Observation Station 5
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a simple solution: select small.a,b from (select city a,length(city) b from station order by b, a)small where rownum=1 union select big.a,b from (select city a , length(city)b from station order by b desc ,a desc)big where rownum=1;
Can you please explain this?
select city,length(city) from (select city , length(city) from (select city from station order by length(city)) as a order by length(city),city limit 1) as b union all select city,length(city) from (select city , length(city) from (select city from station order by length(city)) as c order by length(city) desc,city limit 1) as d
should work for mysql
There is nothing to explain in oracale to select selected number of raw we used ROWNUM and in MUSQL we use LIMIT
IN BIGGEST A SHOULD BE SORTED ASC BECAUSE WE NEED THE FIRST ENTRY NOT THE LAST FOR SAME LENBGTH CASE
wrong. In the last query should be ordered by b desc, a ASC as we have to take the first alphabetically. But the table seems to have only one city with the largest string so you get luckily the expected results.