We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
An extra day is added to the calendar almost every four years as February 29, and the day is called a leap day. It corrects the calendar for the fact that our planet takes approximately 365.25 days to orbit the sun. A leap year contains a leap day.
In the Gregorian calendar, three conditions are used to identify leap years:
The year can be evenly divided by 4, is a leap year, unless:
The year can be evenly divided by 100, it is NOT a leap year, unless:
The year is also evenly divisible by 400. Then it is a leap year.
This means that in the Gregorian calendar, the years 2000 and 2400 are leap years, while 1800, 1900, 2100, 2200, 2300 and 2500 are NOT leap years. Source
Task
Given a year, determine whether it is a leap year. If it is a leap year, return the Boolean True, otherwise return False.
Note that the code stub provided reads from STDIN and passes arguments to the is_leap function. It is only necessary to complete the is_leap function.
Input Format
Read , the year to test.
Constraints
Output Format
The function must return a Boolean value (True/False). Output is handled by the provided code stub.
Sample Input 0
1990
Sample Output 0
False
Explanation 0
1990 is not a multiple of 4 hence it's not a leap year.
Language
Python 3
More
12345678
def is_leap(year):
leap = False
# Write your logic here
return leap
year = int(input())
Line: 8 Col: 20
Test against custom input
BlogScoringEnvironmentFAQAbout
Cookie support is required to access HackerRank
Seems like cookies are disabled on this browser, please enable them to open this website
Write a function
You are viewing a single comment's thread. Return to all comments →
An extra day is added to the calendar almost every four years as February 29, and the day is called a leap day. It corrects the calendar for the fact that our planet takes approximately 365.25 days to orbit the sun. A leap year contains a leap day.
In the Gregorian calendar, three conditions are used to identify leap years:
The year can be evenly divided by 4, is a leap year, unless: The year can be evenly divided by 100, it is NOT a leap year, unless: The year is also evenly divisible by 400. Then it is a leap year. This means that in the Gregorian calendar, the years 2000 and 2400 are leap years, while 1800, 1900, 2100, 2200, 2300 and 2500 are NOT leap years. Source
Task
Given a year, determine whether it is a leap year. If it is a leap year, return the Boolean True, otherwise return False.
Note that the code stub provided reads from STDIN and passes arguments to the is_leap function. It is only necessary to complete the is_leap function.
Input Format
Read , the year to test.
Constraints
Output Format
The function must return a Boolean value (True/False). Output is handled by the provided code stub.
Sample Input 0
1990 Sample Output 0
False Explanation 0
1990 is not a multiple of 4 hence it's not a leap year.
Language Python 3 More 12345678 def is_leap(year): leap = False
year = int(input()) Line: 8 Col: 20
Test against custom input BlogScoringEnvironmentFAQAbout