We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
Loading...
  1. Practice
  2. Python
  3. Introduction
  4. Write a function
  5. Discussions

Write a function

  • zrolpin + 7 comments

    Reversing the order almost works, but you have to add an else block returning False at the end to capture cases where none of the if blocks execute (like for the year 1992) and also change all elif statements to if statements. I.e:

    def is_leap(year):
    if year % 400 == 0:
        return True
    if year % 100 == 0:
        return False
    if year % 4 == 0:
        return True
    else:
        return False

    This passes all the test cases.

    • sjayanthkumar191 + 0 comments

      i will mark your words

    • bmp17c + 0 comments

      not passes year %100 == 0 test

    • danhoffman7 + 1 comment

      Why wouldn't 1992 return true if % 4 == 0 is the first statement? it divides cleanly by 4 with no remainder, yet it gives false in the original scenario.

      • anusha7m + 0 comments

        true

    • dishapandey77 + 0 comments

      why we have to change elif statements to if statements sir??

    • bhatt_siddharth2 + 0 comments

      i did the same thing but it's not working for year 2100 2100 is a leap year,but according to the compiler we should get False.

    • praveennarwal5 + 0 comments

      will u please explain this why if not elif works

    • vijishmadhavan + 1 comment

      why is it % and not / ???

      • saboor_niazi + 0 comments

        because for (year/4, year/100, year/400), you need to insert the answer. And you cannot do that because you do not know all the values for the year variable. If you were to hardcode any year, for instance,

        year = 2000 if year/4 == 500: return True

        I hope this helps.