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public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int i = in.nextInt();
int j = in.nextInt();
int k = in.nextInt();
int numOfBeautifulDays=0;
for(int l=i; l<=j;l++) {
if((l-reverse(l))%k ==0) numOfBeautifulDays++;
}
System.out.println(numOfBeautifulDays);
}
public static int reverse(int number){
int reverse = 0;
while(number!=0){
reverse = 10*reverse +number%10;
number = number/10;
}
reverse += number;
return reverse;
}
Actually there is no need to introduce "reverse += number".It's working well without the use of it.
here is my code:
import java.io.;
import java.util.;
import java.text.;
import java.math.;
import java.util.regex.*;
public class Solution {
public static int reverse(int a)
{
int reverse = 0;
while(a!=0)
{
reverse = reverse * 10;
reverse = reverse + a%10;
a = a/10;
}
return reverse;
}
public static void main(String[] args) {
/* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
Scanner in = new Scanner(System.in);
int i = in.nextInt();
int j = in.nextInt();
int k = in.nextInt();
//int n = i-j+1;
// int s[] = new int[n];
int count = 0;
for(int a = i;a<j+1;a++)
{
int d= a-reverse(a);
if(d%k==0)
count++;
}
System.out.println(count);
}
Beautiful Days at the Movies
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public class Solution {
}
Same idea here
MR.CRAZYPAN
why did you do this reverse += number;
to get reverse of number
"reverse += number;" can you explain me this part?
Actually there is no need to introduce "reverse += number".It's working well without the use of it. here is my code: import java.io.; import java.util.; import java.text.; import java.math.; import java.util.regex.*;
public class Solution {
}
why do you need "reverse += number;"?