Actually there is no need to introduce "reverse += number".It's working well without the use of it. here is my code: import java.io.; import java.util.; import java.text.; import java.math.; import java.util.regex.*;

public class Solution {

public static int reverse(int a)
{

    int reverse = 0;
    while(a!=0)
    {
        reverse = reverse * 10;
        reverse = reverse + a%10;
        a = a/10;
    }
    return reverse;

}

public static void main(String[] args) {
    /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
    Scanner in = new Scanner(System.in);
    int i = in.nextInt();
    int j = in.nextInt();
    int k = in.nextInt();
    //int n = i-j+1;
  //  int s[] = new int[n];
    int count = 0;
    for(int a = i;a<j+1;a++)
    {           
       int d= a-reverse(a);
       if(d%k==0)
           count++;
    }
    System.out.println(count);
}

}