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  1. Practice
  2. Algorithms
  3. Implementation
  4. Grading Students
  5. Discussions

Grading Students

  • jasonganub + 15 comments

    A simple and clean solution with only one print statement and minimal conditionals.

    if grade >= 38:
    if grade % 5 == 3:
        grade += 2
    elif grade % 5 == 4:
        grade += 1
print(grade)

    • jakemager + 1 comment

      awesome use of the modulo operation

      • trungskigoldberg + 1 comment

        this solution is mathematically cool man

        • franchetti + 2 comments

          Could be condensed to a single condition if you wanted.

          if grade >= 38:
    if grade % 5 > 2:
        grade += 5 - (grade % 5)
print(grade)

          • iabhayt + 0 comments

            thanks :)

          • lvsz_ + 0 comments

            That's two, and it could be condensed to none if you wanted.

            print((grade, grade - (grade % -5))[grade >= 38 and grade % 5 > 2])

    • cuteprince1989 + 0 comments

      this is such a clever solution great mind...

    • cuteprince1989 + 1 comment

      it is not working it is giving me error unsupported operand type for %: list and int. can any help me? there compiler is not working correctly, i have run this code in python 2 in my system it is working fine but not in here

      • ThaiNguyen + 0 comments

        You are using grade, which is a list. You have to access the indices in the list using loop like this

        for i in grade:   
    if i >= 38:
        if i % 5 == 3:
            i += 2
        elif i % 5 == 4:
            i += 1
    print (i)

    • h201551072 + 2 comments

      new in python can u help me with this code

      #!/bin/python

import sys

def solve(grades):
    r=[]
    y=0
    d=0
    # Complete this function
    for i in range(0,len(grades)-1):
        if(grades[i]>=38):
            y=grades[i]/5
            d=5*(y+1)-grades[i]
            if(d<3):
                r[i]=5*(y+1)
            else:
                r[i]=grades[i]
        else:
            r[i]=grades[i]
    return r
               

n = int(raw_input().strip())
grades = []
grades_i = 0
for grades_i in xrange(n):
    grades_t = int(raw_input().strip())
    grades.append(grades_t)
result = solve(grades)
print "\n".join(map(str, result))

      • immanoj16 + 2 comments
        def solve(grades):
    result = []
    for i in grades:
        if i >= 38:
            if i % 5 >= 3:
                i += (5 - i % 5)
        result.append(i)
    return result

        • debabrata_tah98 + 0 comments
          [deleted]

        • debabrata_tah98 + 1 comment

          def gradingStudents(grades):

              result = []

for i in range(0, len(grades)):
    grades[i] = int(grades[i])

for i in grades:
    for j in range(1,101):
        if(j%5 == 0 and j>i):
            if(i<38):
                result.append(str(i))
                break
            elif(j-i<3):
                result.append(str(j))
                break
            else:
                result.append(str(i))
                break

return result

          • debabrata_tah98 + 0 comments

            test case 3 and 10 are not passing. can u tell me what is the error?

      • tomarshubham49 + 0 comments

        fgfhyhyrihowhhflhiihiw{} bhai yeah galti hai teri program mmm

    • dylanjcastillo + 0 comments

      Great solution!

    • lukus_2222 + 0 comments

      neat

      heres the same solution in PHP 

      function solve($grades){

for ($i=0;$i <= sizeof($grades); $i++){
    if ($grades[$i] >= 38){
        if ($grades[$i] % 5 == 3){
            $grades[$i] += 2;
        }
        else if ($grades[$i] % 5 == 4){
            $grades[$i] += 1;
        }
    }
}
      
    return $grades;
}

    • 16wh1a05b7 + 0 comments
      [deleted]

    • lvsz_ + 0 comments

      A difficult and intricate solution with only one line and no conditionals (nor variables).

      print . ((uncurry (+) .) . ((. ((*) . fromEnum)) . flip second) <*> (uncurry ((. (>) 3) . (&&) . (<) 37))) . ((,) <*> (flip mod 5 . negate))

    • sammy9292 + 0 comments

      fantastic. Such simple logic!!!

    • max_aka21 + 0 comments

      You can just group 1st and 2nd if condition into single if condition

    • the_happy_hacker + 0 comments
      def gradingStudents(grades):
  return [g if g < 38 or g%5 < 3 else (g//5+1)*5 for g in grades]

    • aryan_kx + 0 comments
      [deleted]

    • cagano + 0 comments

      I am not very happy about float to integer conversion bit. 

      def gradingStudents(grades):
    # Write your code here
    for i in grades:
        if i>37:
            grades[grades.index(i)] = int(max(i, round(i/5,0)*5))
    return grades

    • vallespardojl + 0 comments

      My solution has one conditional less, but your one is very readable

      def gradingStudents(grades):
    for i in range(len(grades)):
        if grades[i]<38:
            pass
        elif grades[i]%5 > 2:
            grades[i] += 5-grades[i]%5
        
    return grades

    • koupy + 1 comment

      hey guys, im a beginner. can someone explain why did he use grade % 5==3 and grade % 5 ==4

      • mbc381575 + 0 comments

        to determine if the element is rounded up or not. 9%5 = 4 , 13%5=3 , 17%5= 2 , 16%5 = 1 and 10%5=0 . First two will round, others not.