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  1. Practice
  2. Java
  3. Exception Handling
  4. Java Exception Handling (Try-catch)
  5. Discussions

Java Exception Handling (Try-catch)

  • allforcatmohit + 0 comments

    This also works:

    import java.io.; import java.util.; import java.text.; import java.math.; import java.util.regex.*;

    public class Solution {

    public static void main(String[] args) {
    /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
    Scanner sc = new Scanner(System.in);
    try{
        int x = sc.nextInt();
        int y = sc.nextInt();
        try{
            int result = x/y;
            System.out.println(result);
        } catch(Exception e){
            System.out.println("java.lang.ArithmeticException: / by zero");
        }
    } catch(Exception e){
        System.out.println("java.util.InputMismatchException");
    }
}

    }