Java Exception Handling (Try-catch)

  • + 0 comments

    This also works:

    import java.io.; import java.util.; import java.text.; import java.math.; import java.util.regex.*;

    public class Solution {

    public static void main(String[] args) {
        /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
        Scanner sc = new Scanner(System.in);
        try{
            int x = sc.nextInt();
            int y = sc.nextInt();
            try{
                int result = x/y;
                System.out.println(result);
            } catch(Exception e){
                System.out.println("java.lang.ArithmeticException: / by zero");
            }
        } catch(Exception e){
            System.out.println("java.util.InputMismatchException");
        }
    }
    

    }