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  1. Practice
  2. Java
  3. Introduction
  4. Java If-Else
  5. Discussions

Java If-Else

  • inanutshellus + 2 comments

    I didn't forget it, it's just not defined as to what I'm supposed to do with 101. My reading of the "constraints" was that the inputs would be between 1 and 100... If the author is now failing you for not taking into account the constraint he should specify what should happen when you're outside the bounds. e.g. throw an exception or print nothing.

    • SanjanaKapoor + 1 comment

      Yeah. It is not mentioned what to do if the number is not between 1 and 100. I am getting errors in test case 3 and 7 for my code which is similar to this one. I dont understand what shud be done.

      • inanutshellus + 2 comments

        Unless the test cases changed, you don't have to account for input outside the range.

        • jangapavanyadav + 12 comments

          import java.io.; import java.util.; import java.text.; import java.math.; import java.util.regex.*;

          public class Solution {


    public static void main(String[] args) {

        Scanner sc=new Scanner(System.in);
        int n=sc.nextInt();            
        String ans="";
        if(n%2==1 || ( (n%2==0) && (n>=6 && n <= 20 ) ) ){
          ans = "Weird";
        }
        else{
            ans = "Not Weird";
           //Complete the code

        }
        System.out.println(ans);

    }
}
          • karthikkrishna97 + 1 comment

            super

          • raghubobba123 + 0 comments
            [deleted]
          • marcyvanbeguide7 + 1 comment

            wow i love your reasonning

          • rajesh96 + 1 comment

            thanks jangapavanyadav

          • tusharbz7276 + 3 comments

            you dont need to add (n%2==0) in if(n%2==1 || ( (n%2==0) && (n>=6 && n <= 20 ) ) ) statement as it is not to checking whether the number is even. we need to check only that number is odd so (n%2==1) is important and number is in bitween 6 to 20. if this doesnot follow go to direct else statement. i ran without (n%2==0) statement and it ran perfectly.

            • jangapavanyadav + 2 comments

              are you kidding :-p , If n is even and in the inclusive range of 6 to 20, print Weird, so you didn't check for the even condition and if nis in the range or 6 to 20 you are printing wired, which is wrong

              • tusharbz7276 + 1 comment

                No i agree with you that it should check the even condition but i dont know what is wrong with the hackerank testing arlgorithm that it is only considering number between 6 to 20(irrespective of even or odd).Go ahead submit the code without n%2==0 condition it does follow all test cases correctly.Thats why i said code is not asking you to check even condition.

                • kaushik_dushyan1 + 0 comments

                  Well even I added n%2==0 condition but we do not need to. As it has been said that if n is odd it is weird and if even numbers between 6-20 are weird then it doesnt matter that the number is even or odd in 6-20 as odd numbers are already weird with the condition n%2==1. So we can have if(n%2==1 || (n>=6 && n<=20)) for the weird condition.

              • chandradhargowt1 + 0 comments

                || is a short hand operator. If the left side is evaluated to true, it doesnt even evaluate the right side expression. If a number is odd, the right side expression isnt even evaluated - if the number isnt odd, then it must be even right? why bother adding n%2==0 again?

            • lohithrathode + 0 comments
              [deleted]
            • Roy_Vandana + 0 comments

              EXACTLY

          • nzdvorak + 0 comments

            You don't need n%2==0. If it's between 6 and 20 inclusive it's Weird. Period. Doesn't matter if it's even or odd.

          • zarana_sheth + 3 comments
                        if(n%2==1 || (n%2==0) && (n>=6 && n<=20) ){
                ans = "Weird";
            }
            else{
              if((n%2==0) && (n>=2 && n<=5) || (n>20)){
                 ans="Not Weird";
                }
            }
            System.out.println(ans);
            • akanjaniuuu + 0 comments

              have you compiled this programme in this website complier?

            • trashdatos + 0 comments
                      String ans="Not Weird";
        if(n%2==1){
          ans = "Weird";
        }
        else{

           if (n>=6 && n<=20)
           {
             ans="Weird";
           }
         }
            • freddie_archie + 0 comments

              worked pefectly!; thanks!!, will study this one more, still a beginner at this.

          • jkalandarov + 0 comments

            Can you explain us how you did this in simpler way? Thanks for being super!

          • imtheone + 3 comments

            The questions says n is even and and between 6 to 20 , by this logic even 7,9,11,13,15,17,19 will print "weird " .? Please expalin .?

            (n>=6 && n <= 20 )
            • reshmav912 + 0 comments

              you have to print odd numbers as well as even numbers in the range of 6 to 20 as weird. to find the even numbers you have to check if n%2==0

            • reshmav912 + 5 comments

              import java.io.; import java.util.;

              public class Solution {

    public static void main(String[] args) {

        Scanner sc=new Scanner(System.in);
        int n=sc.nextInt();            
        String ans="";

        if(n>=1 && n<=100){
            if(n%2==1){
                ans = "Weird";
            }
            else{
                if(n>=2 && n<=5 ){
                   ans= "Not Weird";
                }
                else if (n>=6 && n<=20){
                    ans = "Weird";
                }
                else if(n>20) {
                    ans = "Not Weird";
                }
            }
        }
        else{
            ans="Invalid no! Enter a number between 1 and 100.";
        }

        System.out.println(ans);

    }
}
              • nanidinesh789 + 0 comments

                It is correct.

              • StormSoundar + 0 comments

                Tq dude...

              • ganesh1towhg + 0 comments

                I recently joined a java development company, and this was very useful in my daily works. Thanks for sharing.

              • mehakkaur2212 + 0 comments

                It is showing error for test case 4. Please help.

              • sangsing126 + 0 comments

                String ans=""; --> what's that, please explain

            • abdul_m_talha + 0 comments

              check the if condition..if the number is odd it will print weird and skip the else part. if the 'if' part proves false then by default the number is even ,it will enter the else loop to check for the limit condition and those numbers might be 6,8,10,12,14,16,18,20

          • ahmedayad45 + 0 comments

            where the second condition the number between 2 to 5 ?

          • Manish8087 + 0 comments

            thanks bro...!!

          • sudhanshuprogram + 0 comments

            greAT

        • bhumikadesai17 + 0 comments

          If we dont put the constraints, it is not letting us pass the challenge. I dont know how to put constraints for values.

    • klin6410 + 0 comments

      cool