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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Number Line Jumps
  5. Discussions

Number Line Jumps

  • noman11
     + 0 comments

    Here's a solution in Javascript

    function kangaroo(x1, v1, x2, v2) {
  let val = "NO";
    for(let i=1 ; i<10000; i++){
      if((x1 + i*v1) == (x2 + i*v2)){
        val = "YES"
      }
    }
   return val;
}