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    Java: (x1+n*v1=x2+n*v2)To solve for n, we rearrange the equation:(n*v1-n*v2=x2-x1)(n*(v1-v2)=x2-x1)(n=(x2-x1)/(v1-v2))

    public static String kangaroo(int x1, int v1, int x2, int v2) { // Write your code here String bool ="NO"; if((v1>v2)&&((x2-x1)%(v1-v2)==0)){ bool = "YES"; } return bool; }

    }