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->Product (x2-x1)*(v2-v1) would be >0 when one kangaroo starts ahead of another kangaroo and with greater velocity then another kangaroo. In that case another kangaroo will never be able to catch up.
->Product (x2-x1)*(v2-v1) would be =0 when,
1)Both start with same location but different speed.
2)Both start with different location but same speed.
in either case they will never meet.
eg. 0 5 3 10
(x2-x1)*(v2-v1)>0 First kangaroo will never be able to catch up.
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->Product (x2-x1)*(v2-v1) would be >0 when one kangaroo starts ahead of another kangaroo and with greater velocity then another kangaroo. In that case another kangaroo will never be able to catch up.
->Product (x2-x1)*(v2-v1) would be =0 when,
1)Both start with same location but different speed.
2)Both start with different location but same speed.
in either case they will never meet.
eg. 0 5 3 10
(x2-x1)*(v2-v1)>0 First kangaroo will never be able to catch up.
So what we require is (x2-x1)*(v2-v1)<0.