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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Number Line Jumps
  5. Discussions

Number Line Jumps

  • plmuon
     + 0 comments

    Yes there are a number of conditions to check:

    int num = x2 - x1;
int den = v1 - v2;
if (den == 0) cout << "NO";
else if (num % den != 0) cout << "NO";
else if (num > 0 && den < 0) cout << "NO";
else cout << "YES";

    If x1 < x2 would not be stated, there are just two more conditions to check:

    if (num == 0) cout << "YES";
else if (den == 0) cout << "NO";
else if (num % den != 0) cout << "NO";
else if (num < 0 && den > 0) cout << "NO";
else if (num > 0 && den < 0) cout << "NO";
else cout << "YES";