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  1. Practice
  2. Algorithms
  3. Warmup
  4. Staircase
  5. Discussions

Staircase

  • CodeAcharya + 6 comments

    How about this mate

    public class Solution {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        for(int i=1;i<=n;i++)
        {
             for(int k=n;k>i;k--)
             {
                 System.out.printf(" ");
             }    
             for(int j=1;j<=i;j++)
             {
                 System.out.printf("#");
             }
            System.out.println();
        }
    }
}
    • deekshithsagar73 + 0 comments

      might

    • joaquimley + 3 comments

      3 nested for loops? There's def. something to be improved here, think about recursion.

      • tatianaensslin + 0 comments

        its really only 2 nested for loops and therye each operating on different ranges.

      • benaffleks + 1 comment

        2 nested loops and the size is extremely small so computation time is not something we need to consider

        • bineykingsley36 + 0 comments

          how do you see my Python 2 solution?

      • dallas3 + 1 comment
        function createString(str, ns, n) {
    if (ns > 0) return createString(str+" ", ns-1, n);
    else if (n > 0 && ns === 0) return createString(str+"#", ns, n-1);
    else if (n === 0 && ns === 0) return str;
}

// Complete the staircase function below.
function staircase(n) {
   let ns = n.length-1;
    console.log(createString("", ns, n));

}

        i was going to add a while loop but i keep getting undefined not sure the problem.

        • dallas3 + 0 comments

          okay im an idiot and for some reason put n.length as if a int has a length.

    • hissamrocks + 0 comments

      fantastic idea dude

    • vigneshwar028 + 0 comments

      can you explain this ?

    • Callum_g_anders1 + 0 comments

      That was my solution basically as well. I like it ;)

    • Phiber_Optik + 1 comment

      i m still confused with the logic, can you please explain it furthure more?

      • bineykingsley36 + 2 comments
        1. I loop from 1 to the maximum number (n).
        2. And then I print a number of # amounting to the current loop index on each line followed with a newline break.
        3. But since this will lead to the output being aligned on the left, I also print (n-i) spaces on each line where n is the maximum number and i is the current loop index before executing (2). So for instance when i is 1, I print 5 spaces before I print 1 # to fill up the six spaces (total number of spaces on each line). When i is 2, I print 4 spaces before I print 2 # to make sure all the six spaces on the line are filled. This also ensures that the # is aligned to the right.

        NB. The range is (1, n+1). I didn't start from 0 because that will cause an empty space at the beginning of the output and I also ended at n+1 because the loop ends and n-1 so I add 1 to get to the correct n.

        Do you get it now?

        • Phiber_Optik + 1 comment

          Yes! you explained it awesome. Thank you man!

        • proraviki + 0 comments

          void staircase(int n) { int i,j; for(i=n;i>0;i--) { for(j=1;j<=n;j++) { if(j>=i) { printf("#"); } else printf(" ");

          }
printf("\n");

          }

          } thankx man