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And then I print a number of # amounting to the current loop index on each line followed with a newline break.
But since this will lead to the output being aligned on the left,
I also print (n-i) spaces on each line where n is the maximum number and i is the current loop index before executing (2). So for instance when i is 1, I print 5 spaces before I print 1 # to fill up the six spaces (total number of spaces on each line). When i is 2, I print 4 spaces before I print 2 # to make sure all the six spaces on the line are filled.
This also ensures that the # is aligned to the right.
NB. The range is (1, n+1). I didn't start from 0 because that will cause an empty space at the beginning of the output and I also ended at n+1 because the loop ends and n-1 so I add 1 to get to the correct n.
Staircase
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i m still confused with the logic, can you please explain it furthure more?
NB. The range is (1, n+1). I didn't start from 0 because that will cause an empty space at the beginning of the output and I also ended at n+1 because the loop ends and n-1 so I add 1 to get to the correct n.
Do you get it now?
Yes! you explained it awesome. Thank you man!
void staircase(int n) { int i,j; for(i=n;i>0;i--) { for(j=1;j<=n;j++) { if(j>=i) { printf("#"); } else printf(" ");
}
} thankx man